char *strcpy(char *s1, const char *s2)
將字符串s2復(fù)制到字符串?dāng)?shù)組s1中,返回s1的值
char *strncpy(char *s1, const char *s2, size_t n)
將字符串s2中最多n個(gè)字符復(fù)制到字符串?dāng)?shù)組s1中,返回s1的值
char *strcat(char *s1, const char *s2)
將字符串s2添加到字符串s1的后面。s2的第一個(gè)字符重定義s1的null終止符。返回s1的值
char *strncat(char *s1, const char *s2, size_t n)
將字符串s2中最多n個(gè)字符添加到字符串s1的后面。s2的第一個(gè)字符重定義s1的null終止符。返回s1的值
int strcmp(const char *s1, const char *s2)
比較字符串s1和字符串s2。函數(shù)在s1等于、小于或大于s2時(shí)分別返回0、小于0或者大于0的值
int strncmp(const char *s1, const char *s2, size_t n)
比較字符串s1中的n個(gè)字符和字符串s2。函數(shù)在s1等于、小于或大于s2時(shí)分別返回0、小于0或者大于0的值
char * strtok(char *s1,const char *s2)
用一系列strtok調(diào)用將s1字符串標(biāo)記化(將字符串分成各個(gè)邏輯組件,如同一行文本中的每個(gè)單詞),用字符串s2所包含的字符分隔。 首次調(diào)用時(shí)包含s1為第一個(gè)參數(shù),后面調(diào)用時(shí)繼續(xù)標(biāo)記化同一字符串,包含NULL為第一個(gè)參數(shù)。每次調(diào)用時(shí)返回當(dāng)前標(biāo)記指針。如果函數(shù)調(diào)用時(shí)不再有更多標(biāo)記,則返回NULL
size_t strlen(const char *s)
確定字符串長(zhǎng)度,返回null終止符之前的字符數(shù)
使用示例:
//源代碼在Visual c++6.0環(huán)境下編譯通過
#include
#include
int main()
{
char str1[50] = "Happy birthday to ", str2[] = "coffeehu";
char temp1[100],temp2[6], * temp;
char str[] = "This is a sentence with 7 tokens";
strcpy(temp1, str1);
strncpy(temp2, str1, 5);
temp2[5] = '\0';
cout << "strcpy result: " <
cout << "strncpy result: " << temp2 << "\n";
cout << "strcat result: " << strcat(str1, str2) << "\n";
cout << "strncat result: " << strncat(str1, str2, 6) <<"\n";
cout << "strcmp result: " << strcmp(temp2,"Happ") <<"\n";
cout << "strncmp result: " << strncmp(str1,"Happy",5) <<"\n";
//strtok function eg.
temp = strtok(str, " ");
while(temp != NULL)
{
cout << temp <<'\n';
temp = strtok(NULL, " ");
}
cout << "strlen result: " << strlen(str2) <<"\n";
return 0;
}
將字符串s2復(fù)制到字符串?dāng)?shù)組s1中,返回s1的值
char *strncpy(char *s1, const char *s2, size_t n)
將字符串s2中最多n個(gè)字符復(fù)制到字符串?dāng)?shù)組s1中,返回s1的值
char *strcat(char *s1, const char *s2)
將字符串s2添加到字符串s1的后面。s2的第一個(gè)字符重定義s1的null終止符。返回s1的值
char *strncat(char *s1, const char *s2, size_t n)
將字符串s2中最多n個(gè)字符添加到字符串s1的后面。s2的第一個(gè)字符重定義s1的null終止符。返回s1的值
int strcmp(const char *s1, const char *s2)
比較字符串s1和字符串s2。函數(shù)在s1等于、小于或大于s2時(shí)分別返回0、小于0或者大于0的值
int strncmp(const char *s1, const char *s2, size_t n)
比較字符串s1中的n個(gè)字符和字符串s2。函數(shù)在s1等于、小于或大于s2時(shí)分別返回0、小于0或者大于0的值
char * strtok(char *s1,const char *s2)
用一系列strtok調(diào)用將s1字符串標(biāo)記化(將字符串分成各個(gè)邏輯組件,如同一行文本中的每個(gè)單詞),用字符串s2所包含的字符分隔。 首次調(diào)用時(shí)包含s1為第一個(gè)參數(shù),后面調(diào)用時(shí)繼續(xù)標(biāo)記化同一字符串,包含NULL為第一個(gè)參數(shù)。每次調(diào)用時(shí)返回當(dāng)前標(biāo)記指針。如果函數(shù)調(diào)用時(shí)不再有更多標(biāo)記,則返回NULL
size_t strlen(const char *s)
確定字符串長(zhǎng)度,返回null終止符之前的字符數(shù)
使用示例:
//源代碼在Visual c++6.0環(huán)境下編譯通過
#include
#include
int main()
{
char str1[50] = "Happy birthday to ", str2[] = "coffeehu";
char temp1[100],temp2[6], * temp;
char str[] = "This is a sentence with 7 tokens";
strcpy(temp1, str1);
strncpy(temp2, str1, 5);
temp2[5] = '\0';
cout << "strcpy result: " <
cout << "strncpy result: " << temp2 << "\n";
cout << "strcat result: " << strcat(str1, str2) << "\n";
cout << "strncat result: " << strncat(str1, str2, 6) <<"\n";
cout << "strcmp result: " << strcmp(temp2,"Happ") <<"\n";
cout << "strncmp result: " << strncmp(str1,"Happy",5) <<"\n";
//strtok function eg.
temp = strtok(str, " ");
while(temp != NULL)
{
cout << temp <<'\n';
temp = strtok(NULL, " ");
}
cout << "strlen result: " << strlen(str2) <<"\n";
return 0;
}