javascript解決URL傳值時亂碼的方法

    URL中出現(xiàn)空格，等字符會亂碼，這個是見到的一個比較不錯的處理方式。調(diào)用時，把要傳遞的參數(shù)通過這個js方法轉(zhuǎn)化一下就可以轉(zhuǎn)化為%xx組成的一系列字符 服務(wù)端正常獲取 有興趣的可以試一下 ，具體代碼如下：
    function encodeURL(str){
    var s0, i, s, u;
    s0 = ""; // encoded str
    for (i = 0; i < str.length; i++){ // scan the source
    s = str.charAt(i);
    u = str.charCodeAt(i); // get unicode of the char
    if (s == " "){s0 += "+";} // SP should be converted to "+"
    else {
    if ( u == 0x2a || u == 0x2d || u == 0x2e || u == 0x5f || ((u >= 0x30) && (u <= 0x39)) || ((u >= 0x41) && (u <= 0x5a)) || ((u >= 0x61) && (u <= 0x7a))){ // check for escape
    s0 = s0 + s; // don't escape
    }
    else { // escape
    if ((u >= 0x0) && (u <= 0x7f)){ // single byte format
    s = "0"+u.toString(16);
    s0 += "%"+ s.substr(s.length-2);
    }
    else if (u > 0x1fffff){ // quaternary byte format (extended)
    s0 += "%" + (oxf0 + ((u & 0x1c0000) >> 18)).toString(16);
    s0 += "%" + (0x80 + ((u & 0x3f000) >> 12)).toString(16);
    s0 += "%" + (0x80 + ((u & 0xfc0) >> 6)).toString(16);
    s0 += "%" + (0x80 + (u & 0x3f)).toString(16);
    }
    else if (u > 0x7ff){ // triple byte format
    s0 += "%" + (0xe0 + ((u & 0xf000) >> 12)).toString(16);
    s0 += "%" + (0x80 + ((u & 0xfc0) >> 6)).toString(16);
    s0 += "%" + (0x80 + (u & 0x3f)).toString(16);
    }
    else { // double byte format
    s0 += "%" + (0xc0 + ((u & 0x7c0) >> 6)).toString(16);
    s0 += "%" + (0x80 + (u & 0x3f)).toString(16);
    }
    }
    }
    }
    return s0;
    }